By LearningExpress Editors

ISBN-10: 1576854345

ISBN-13: 9781576854341

501 Quantitative comparability Questions is helping arrange scholars for key educational flair tests-including the PSAT/NMSQT, the SAT, and the GRE-which function a quantitative comparability part in the math component to the examination. 501 Quantitative comparability Questions is designed to aid scholars organize for this really good math part, mastery of that is crucial for attractiveness to fascinating faculties and jobs. by means of finishing the workouts during this e-book, scholars can elevate their math wisdom and achieve familiarity with really expert questions had to ranking excessive. The booklet beneficial properties whole solutions, every one with a whole rationalization

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Sample text

A. Both x and y are negative. Therefore, the sum of x and y is negative (quantity B). The absolute value of x and y are both positive, so their sum is positive (quantity A). Any positive number is greater than any negative number. 79. d. The relationship cannot be determined. If x = −2, then quantity A is 7(3(−2) + 1) = 7(−6 + 1) = 7(−5) = −35 and quantity B is 12(3(−2) + 1) = 12(−6 + 1) = 12(−5) = −60. In this case, quantity A is greater. If x = 2, then quantity A is 7(3(2) + 1) = 7(6 + 1) = 7(7) = 49 and quantity B is 12(3(2) + 1) = 12(6 + 1) = 12(7) = 84.

54. b. If 70% of students passed, 30% of students failed. Therefore, the ratio of failed to passed is 30 to 70, which simplifies to ᎏ37ᎏ. 3 3 ᎏ5ᎏ > ᎏ7ᎏ. 55. c. Add the numbers inside the parentheses. (84 + 12)(15 + 91) = (96)(106) and (74 + 22)(20 + 86) = (96)(106). 56. c. 5. 57. a. Since the bases are equal, just compare the exponents to compare the expressions. 3 > ᎏ13ᎏ. 58. c. 4x is an even number because any multiple of 4 is even. The remainder when an even number is divided by 2 is 0. 59. b.

B. If 70% of students passed, 30% of students failed. Therefore, the ratio of failed to passed is 30 to 70, which simplifies to ᎏ37ᎏ. 3 3 ᎏ5ᎏ > ᎏ7ᎏ. 55. c. Add the numbers inside the parentheses. (84 + 12)(15 + 91) = (96)(106) and (74 + 22)(20 + 86) = (96)(106). 56. c. 5. 57. a. Since the bases are equal, just compare the exponents to compare the expressions. 3 > ᎏ13ᎏ. 58. c. 4x is an even number because any multiple of 4 is even. The remainder when an even number is divided by 2 is 0. 59. b. ͙4 ෆ = 2, so ͙5 ෆ > 2.

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